Question 13
For a normal distribution, the proportion located between z = –1.00 and z = 0 is
95% |
50% |
68.12% |
34.13% |
Using standard normal z-table we find, P(-1.00 < Z < 0)
P(-1.00 < Z < 0)
= P(Z < 0) - P(Z < -1.00)
= 0.5000 - 0.1587
= 0.3413
=> P(-1.00 < Z < 0) = 0.3413
Therefore, the proportion located between z = -1.00 and z = 0 is, 34.13%
Question 13 For a normal distribution, the proportion located between z = –1.00 and z =...
Find the proportion of the normal distribution that is located between the following z-values. (Round your answers to four decimal places.) (a) Between z = 0.50 and z = −0.50. (b) Between z = 1.00 and z = −1.00. (c) Between z = 0 and z = −1.50. (d) Between z = 1.75 and z = −0.25.
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