Question

In C please!

4.20 LAB: Countdown until matching digits Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and stopping when both output digits are identical. Ex: If the input is: 93 the output is: 93 92 91 90 89 88 Ex: If the input is: 77 the output is: 77 Ex: If the input is: 15 or any number not between 20 and 98 (inclusive), the output is: Input must be 20-98 For coding simplicity, follow each output number by a space, even the last one. Use a while loop. Compare the digits; do not write a large if-else for all possible same-digit numbers (11, 22, 33, …, 88), as that approach would be cumbersome for larger ranges.

#include <stdio.h>

int main(void) {

/* Type your code here. */

return 0;
}

Answer 1

#include <stdio.h>

int main() {
    int n, i;
    scanf("%d", &n);
    if (n < 20 || n > 98) {
        printf("Input must be 20-98");
    } else {
        i = n;
        while (1) {
            printf("%d ", i);
            if (i%10 == i/10) {
                break;
            }
            i--;
        }
    }
    return 0;
}