An air parcel that has a temperature of 20 C and a dewpoint of 10 C at sea-level is forced to rise over a mountain that is 3 km high. Given the the appropriate MOIST ADIABATIC LAPSE rate is 5C/km, what would the temperature (in Celsius) of the air parcel be when it reaches the top of the mountain
Answer:
An air parcel would then be called saturated when its temperature and dew point are same. Now, as we know, rising unsaturated air cools at dry adiabatic lapse rate, which is 10o C/km, so, after the air parcel reaches 1 km, the temperature becomes (20 - 10)o C = 10o C, and thus making the air parcel saturated as both the temperature and dew point becoming equal. And after this height, the rising saturated air will then be cooled at moist adiabatic lapse rate, which is 5o C/km here. Thus, for the rest 2 km, the temperature becomes 10 - (5*2) = 0o C at the top of the mountain.
An air parcel that has a temperature of 20 C and a dewpoint of 10 C...
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