Question

The value of Ka for nitrous acid (HNO2) at 25 ∘Cis 4.5×10−4. You may want to reference(Pages 833 - 836) Section19.7 while completing this problem.

Part A Write the chemical equation for the equilibrium that corresponds to Ka. Write the chemical equation for the equilibrium that corresponds to . H+(aq)+NO2−(aq)⇌HNO2(aq) HNO2(aq)⇌H+(aq)+NO2−(aq) HNO2(aq)⇌H−(aq)+NO2+(aq) HNO2(aq)+H+(aq)⇌H2NO2+(aq) HNO2(aq)+H−(aq)⇌H2NO2+(aq) Part B Using the value of Ka, calculate ΔG∘ for the dissociation of nitrous acid in aqueous solution. Express your answer using three significant figures. ΔG∘ ΔG∘ = nothing   kJ   Part C What is the value of ΔG at equilibrium? Express your answer using one significant figure. ΔG ΔG = nothing   kJ   Part D What is the value of ΔG when [H+] = 5.6×10−2M , [NO−2] = 6.3×10−4M and [HNO2] = 0.21 M ? Express your answer using three significant figure. ΔG ΔG = nothing   kJ