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The KbKb for methylamine (CH3NH2)(CH3NH2) at 25 ∘C∘C is 4.4×10−44.4×10−4. Part B. By using the value...

The KbKb for methylamine (CH3NH2)(CH3NH2) at 25 ∘C∘C is 4.4×10−44.4×10−4.

Part B. By using the value of KbKb, calculate ΔG∘ΔG∘ for the equilibrium in part A.

Part D. What is the value of ΔGΔG when [H+][H+] = 6.6×10−9 MM, [CH3NH+3][CH3NH3+] = 2.5×10−3 MM, and [CH3NH2][CH3NH2] = 9.70×10−2 MM?

The value of KaKa for nitrous acid (HNO2)(HNO2) at 25 ∘C∘C is 4.5×10−44.5×10−4. You may want to reference (Pages 833 - 836) Section19.7 while completing this problem.

1. Using the value of KaKa, calculate ΔG∘ΔG∘ for the dissociation of nitrous acid in aqueous solution.

2. What is the value of ΔGΔG when [H+][H+] = 5.6×10−2M5.6×10−2M , [NO−2][NO2−] = 6.2×10−4M6.2×10−4M and [HNO2][HNO2] = 0.21 MM ?

Consider the decomposition of barium carbonate: BaCO3(s)←→BaO(s)+CO2(g)

1. Using data from Appendix C in the textbook, calculate the equilibrium pressure of CO2CO2 at 1250 KK .

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Answer #1

Anster) We know that the relation between sa and ky is given by the formula, sh = - RT anko .... where, saº e standard gibbsNow putting the above values in equation @ we get 1a = 1914616 J. moi +8.314 Jimon. K7 x 298 x In (3.899x109) a, sh = 19146

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