Question

____ 16. State your conclusion to the hypothesis test.

A local retailer currently schedules employees based on the assumption that they serve customers uniformly throughout the week (the same number each day). Management is starting to question this assumption and decides to collect data on the number of customers served each day of the week to perform a Chi-Square goodness-of-fit test at a 5% significance level.

Monday Tuesday Wednesday Thursday Friday Total

Number Served 40 33 35 32 60 200

Provided the assumptions of the test are satisfied, state your conclusion to the test. Note: the p-value = 0.01

a) Cannot be determined.

b) There is insufficient evidence to conclude that customers are unevenly distributed throughout the week.

c) There is sufficient evidence to conclude that customers are unevenly distributed throughout the week.

Answer 1

Answer: c) There is sufficient evidence to conclude that customers are unevenly distributed throughout the week.

Explanation: The null and alternative hypothesis is:

H0: The customers are uniformly distributed throughout the week.

H1: The customers are unevenly distributed throughout the week.

The p-value of Chi-square goodness-of-fit test is 0.01. This p-value is less than 0.05. Hence we reject null hypothesis at 5% level of significance and conclude that there is sufficient evidence to conclude that customers are unevenly distributed throughout the week.