5 )
The hypothesis are :
H0 : Bicycle deaths occur with equal frequency with respect to day.
H1: Bicycle deaths occur with unequal probability with respect to day.
The test statistic is
O = Observed frequency
E = Expected frequency
E = N* p
All days have same probability. So p = 1/7 and N= 200.
Hence expected frequency = E = 200 * 1/7 = 28.57 for each day.
O | E | |
16 | 28.57 | 5.530 |
35 | 28.57 | 1.447 |
16 | 28.57 | 5.530 |
28 | 28.57 | 0.011 |
34 | 28.57 | 1.032 |
41 | 28.57 | 5.408 |
30 | 28.57 | 0.072 |
Total | 19.031 |
So, test statistic is
= 19.031
df = Number of days - 1 = 7 -1 = 6 , = 0.05
In the chi square probability table , we look across df = 6 and probability 0.05 .
So the critical value =
Here calculated value of > critical value of
Hence we reject null hypothesis.
Conclusion : There is no evidence to believe that bicycle deaths occur with unequal frequency with respect to day.
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