The electron in a Be3+ ion is in an orbit with n=6. What is the energy...

Question

Question

The electron in a Be3+ ion is in an orbit with n=6. What is the energy of the electron in this orbit?

Answer 1

Answer #1

energy = K x Z^2 / n^2

Z = atomic number of Be = 4

n = 6 is given

energy = K x Z^2 / n^2

= 2.179 x 10^-18 x 4^2 / 6^2

= 9.684 x 10^-19 J

energy = 9.684 x 10^-19 J

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Answer 2

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