Target distance determined by speed and round trip time of pulse. The third piece of information needed is the distance (D) from radar to target.
Distance is determined by measuring the time it takes for the pulse to make a round trip from the radar to the target and back using the relation distance = (time) * (velocity). The velocity is the speed of light, the speed at which the pulse travels (c). Since the pulse has to travel to the target and back, the total distance is 2D. If t is the time it takes, then 2D = ct or D = ct/2. Using the calculated distance, azimuth angle and elevation angle, the exact location of the target can be determined. Thank you!!!
dind the distance to a radar target for the following reound trip delay times
Why does radar employ the technique called pulse delay ranging?
Why does radar employ the technique called pulse delay ranging?
Suppose a 5GHz radar with antenna of effective area Ae-5 m 2 transmits 100kW. If a target with a 12mA2 RCS is 101km away, (a) what is the round trip travel time for the radar pulse? (b) what is received power?
Suppose a 5GHz radar with antenna of effective area Ae-5 m 2 transmits 100kW. If a target with a 12mA2 RCS is 101km away, (a) what is the round trip travel time for the radar pulse? (b) what is...
Explain your responses in reasonable details. Very brief answers are not acceptable 1) Why does radar employ the technique called pulse delay ranging? (Spts) 2) Speed of light-3x10ms Round-Trip Time-20 μ Calculate Range to the target aircraft.(Spts) 3) to figure above. The measured frequency difference is 10,000 hertz and the transmitter (Spts) has been increasing at a rate of 10 hertz per microsecond. Calculate range. 2) Speed of light 3x108 m/s Round-Trip Time 20 us Calculate Range to the target...
How long would a radar signal take to complete a round-trip between Earth and Mars when the two planets are 0.7 AU apart?
Consider a radar with the following specifications: f = 1250MHz, maximum radar range of 220 nautical miles, for target with radar cross section σ = 1m ^ 2 with radar antenna dimensions 12 × 4m Antenna aperture efficiency ε_a = 0.55, minimum detectable signal of a pulse S_npn = 10 ^ (- 13) W and pulse width τ = 1.5μs. Calculate the following values: A) Effective A_em aperture level and G gain in terms of dB radar antenna. B) Transmitter...
The measured average round trip delay on a connection is 50 msec. If the link has a bandwidth of 1Gb/sec, what is the minimum number of Bytes that should be available in the window so that the transfer of the data does not become stop and wait
Calculate the average round-trip travel distance and travel time
for each zone. Assume that people in Zone 0 have a travel distance
and time of zero. Every other zone has increasing travel time and
distance. Next, using average cost per mile and per hour of travel
time, calculate the travel cost per trip. A
standard cost per mile for operating an automobile is readily
available from AAA or similar sources. Assume that cost per mile is
$.30, or use the...
11. Suppose the bandwidth on a point-to-point link is 1 Mbps and the round-trip delay is 19 milliseconds. Assume that the size of each packet is 1000 bits. Also assume that the size of ACK packet is negligible. Answer each of the following for both go-back-n and selective-repeat schemes. Assume that the sender always has data for transmission. (10 points) (a) Assuming that the link is error-free, what should be the minimum window size to achieve at least 75% utilization....
A Radar transmits a 6µSec pulse observed two targets at the same azimuth and elevation. One target is 610 m behind the other. Since this distance is less than the range resolution, only one pulse will be received. How long will this pulse live? (c=3x108)
Match the following descriptions of Naomi's trip to the segments identified on the following distance-time graph. Note: segments may be chosen more than once. 10 9 Distance from home (miles) 5 1 9:00 10:00 11:00 12:00 13:00 14:00 15:00 16:00 17:00 18:00 Time of the day Naomi is stopped 10 km away from her house. Naomi is moving the fastest towards her house. 1. Segment A Naomi is stopped for one hour. 2. Segment B 3. Segment 4. Segment D...