Question

In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two respondents were from the same​ household.) Among the​ respondents, 205 answered​ "none," 289 said​ "one," 366 said​ "two," 134 said​ "three," and 45 responded with four or more. A survey respondent is selected at random. Find the probability that​ his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in​ use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

P(four or more cell ​phones)= ​(Round to three decimal places as​ needed.)

Answer 1

P(Four or more cell phones)

= 45 / (205 + 289 + 366 + 134 + 45)

= 45 / 1039

= 0.043

This event is unusual because its probability is less than 0.05