Question

In a survey of consumers aged 12 and older, respondents were asked how many cell phones were in use by the household. (No two respondents were from the same household.) Among the respondents,

201201

answered "none,"

281281

said "one,"

359359

said "two,"

142142

said "three," and

128128

responded with four or more. A survey respondent is selected at random. Find the probability that his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

P(four or more cell

phones)equals=nothing

(Round to three decimal places as needed.)

Answer 1

P(four or more cell phones) =number of people with four or more cell phones/total number of people

=128/(201+281+359+142+128)=0.115