Question

A random sample o 100 cars on Fry Road recently produced the following result, for a...

A random sample o 100 cars on Fry Road recently produced the following result, for a "Z-interval for proportions, 90% confidence": 0.3012 < p(Japanese) < 0.4853".

State specifically the meaning and interpretation of this statement.

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Answer #1

From the given information

90 % confidence interval interval estimate for the population proportion of Japanese cars on the fry road is

0.3012 < P < 0.4853

We can interpret this as

We are 90 % confidant that the population proportion of Japanese cars on Fry road is between 0.3012 and 0.4853.

Also we can say that with 90 % confidence

Percentage of Japanese cars on the Fry road is between 30.12% and 48.53 %.

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