The probability that a person who booked a flight will actually show up is 0.95. If the airline books 104 people on a flight for which the maximum capacity is 100, what is the probability that there will be enough seats for everyone who shows up? Round your answer to 3 decimal places.
X ~ Bin ( n , p)
Where n = 104 , p = 0.95
Mean= np = 104 * 0.95 = 98.8
SD = sqrt ( n p( 1 - p) ) = sqrt ( 104 * 0.95 ( 1 - 0.95 )) = 2.2226
Using normal approximation
P(X < x) = P(Z < ( x - mean) / SD )
With continuity correction
P(X <= 100 ) = P(Z < (100.5 - 98.8) / 2.2226)
= P(Z < 0.76)
= 0.776
The probability that a person who booked a flight will actually show up is 0.95. If...
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