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what was the original molarity of a solution that diluted 5.0ml to 25.0 ml and had...

what was the original molarity of a solution that diluted 5.0ml to 25.0 ml and had a final molarity of 1.25M

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Answer #1

Answer:

Given final molarity=1.25 M and volume=25 mL.

Here you have to use M1V1 = M2V2

M1=?, V1=5 mL, M2=1.25 M, V2=25 mL.

M1=M2V2/V1=(1.25 M x 25 mL)/(5 mL)

M1=6.25 M.

Therefore the original molarity of solution=6.25 M.

Please let me know if you have any doubt. Thanks and I hope you like it.

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