Consider the path of the proton (q = 1.602 × 10−19 C, m = 1.673
× 10−27 kg) in a uniform electric and magnetic field. Both fields
are in the z direction, B⃗ = B0k? and E⃗ = E0k?, where B0 = 55 mT
and E0 = 180 V / m. At time t = 0, the proton moves at v⃗ = v0?ı,
v0 = 150 km / s. Based on this information, what kind of orbit does
the proton have?
(a) Calculate the radius of the thread and the pitch of the thread
in the first and second turns. (b) Draw the proton path.
Consider the path of the proton (q = 1.602 × 10−19 C, m = 1.673 ×...
s. A proton, m 1.6726 x 1027 kg, q = 1.602 x 1019 [CI, moves in a circular path of radius r 0.03 [mi, perpendicular to the magnetic field B-5 [μη into the page. Find a. v, velocity b. Fa, magnetic force c. T, the period (the time for one complete circle) Bin
Problem 4. (10 pts.) A proton moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.00 mt. If the speed of the electron is 1.52 x10 m/s, determine (a) the radius of the circular path. (c) the time interval required to complete one revolution.
A stream of protons (m = 1.67265 times 10^-27 kg; q = 1.602 times 10^-19 C) traveling at various speeds is sent through a velocity selector. The velocity selector has an electric field of 4.82 times 10^6 N/C and a magnetic field of 1.06 T. Immediately after the velocity selector is a region of the same magnetic field but no electric field. What is the radius of the path traveled by the stream of protons that emerge from the velocity...
X 107 kg) 27.25 A proton (q 1.60 x 1019 C, m 1.67 moves in a uniform magnetic field B (0.500 T)1. At t = 0 the proton has velocity components ux-1.50 × 105 m/s, vy=0, and vz = 2.00 × 105 m/s (see Example 27.4) (a) what are the magnitude and direction of the magnetic force acting on the proton? In addition to the magnetic field there is a uniform electric field in the +x-direction, E (+2.00 x 104...
1) A proton (q= 1.6 X 10^-19 C) moves along a uniform E-field ( 3.0 v/m) for a distance of 10 cm. what is the change in kinetic energy of the proton? a) 4.0 X 10^-19 J b) 8.6 X 10^-20 J c) 4.8 X 10^-20 J d) 1.6 X 10^-21 J 2) When a charged particle moves from a higher equipotential surface to a lower equipotential surface what is the nature of the work done by the electric field?...
PLEASE HELP ME AND SHOW STEPS. THANK YOU 1) It is desined to step up a vollage of 120 V to 96,000 v. The turns ratio N/N, of the transformer a) I/28 b) (64 x 10y )28 d) 8001 if the voltage is stepped that power is not lost in an ideal transformer, consider the situation in the above question. 2) Starting from the idea t up 800 times, the current is a) the same, since power is the same...