A stream of protons (m = 1.67265 times 10^-27 kg; q = 1.602 times 10^-19 C)...
Consider the path of the proton (q = 1.602 × 10−19 C, m = 1.673 × 10−27 kg) in a uniform electric and magnetic field. Both fields are in the z direction, B⃗ = B0k? and E⃗ = E0k?, where B0 = 55 mT and E0 = 180 V / m. At time t = 0, the proton moves at v⃗ = v0?ı, v0 = 150 km / s. Based on this information, what kind of orbit does the proton...
s. A proton, m 1.6726 x 1027 kg, q = 1.602 x 1019 [CI, moves in a circular path of radius r 0.03 [mi, perpendicular to the magnetic field B-5 [μη into the page. Find a. v, velocity b. Fa, magnetic force c. T, the period (the time for one complete circle) Bin
An electron (m_p = 9.1 times 10^-31 kg, q_p = -1.6 times 10^-19 C) travels at 4 times 10^5 m/s in a direction perpendicular to a uniform 3.0 mT magnetic field. What is the diameter of its path? Two long straight wires each carrying a current of 200 A in the same directions are separated by a distance of 40 cm. Calculate the force on a 2m long section of wire. Is the force attractive or repulsive? An electron is...
(ex) The electric field is 1.20 times 10^6 N/C between plates 1 and 2, but is zero everywhere else in the figure. The magnetic field is 0.600 T everywhere in the figure. After passing straight through the region between the plates, aluminum ions enter the region with only a magnetic field, move in a circular path of radius 0.899 m there, and finally hit the photographic plate. a) The region between plates 1 and 2 is a "velocity selector": Only...
A. An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that has a value of 1.67 × 106 V and then enters a uniform magnetic field whose magnitude is 2.49 T. The α-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the α-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its...
A proton (m= 1.67e-27 kg) is accelerated from rest through a potential difference of 11.5 kV before entering a velocity selector. If the B- field of the velocity selector is perpendicular to the velocity and the electric field (E) has a magnitude of 3.5e6 N/C, what is the required magnitude of the magnetic field (B) if the proton is undeflected?
An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C. A) what is the change in electric potential if the election moves 1cm in the direction of the electric field? B)What is the change in electric potential energy if the electron moves 1 cm in the direction of the electric field?C) What is the change in electric potential if the election is 1 cm perpendicular to the electric field?D) What is the change in...
An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C. A) what is the change in electric potential if the election moves 1cm in the direction of the electric field? B)What is the change in electric potential energy if the electron moves 1 cm in the direction of the electric field?C) What is the change in electric potential if the election is 1 cm perpendicular to the electric field?D) What is the change in...
An alpha-particle has a charge of +2e and a mass of 6.64 times 10^-27 kg. It is accelerated from rest through a potential difference that has a value of 1.24 times 10^6 v and then enters a uniform magnetic field whose magnitude is 3.30 T. The alpha-particle moves perpendicular to the magnetic field at all times. (a) What is the speed of the alpha-particle? m/s (b) What is the magnitude of the magnetic force on it? N (c) What is...
A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E =3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the...