A solution containing 3.47 mM X (analyte) and 1.72 mM S (Standard) gave peak areas of...
A solution containing 3.47 mM X (analyte) and 1.72 mM S (Standard) gave peak areas of 3.473 and 10222, respectively, in a chromatographic analysis. Then 1mL of 8.47 mM S was added to 5mL of unknown X, and the mixture was diluted to 10mL. This solution gave a peak areas of 5,428 and 4,431 for X and S, respectively.
a.) Calculate the response factor for the analyte.
b.) Find the concentration of S (mM) in the 10mL mixture.
c.) Find the concentration of X (mM) in the 10mL mixture. ( For this step please break down every step)
d.) FInd the concentration of X in the original unknown.
Homework Answers
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A solution containing 3.47 mM X (analyte) and 1.72 mM S
(Standard) gave peak areas of...
5-29. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas...
5-29. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3 473 and 10 222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was diluted to 10.0 mL This solution gave peak areas of 5 428 and 4 431 for X and S respectively (a) Calculate the response factor for the analyte (b) Find the concentration of S...
Consider a solution containing 4.69 mM of an analyte, X, and 1.22 mM of a standard,...
Consider a solution containing 4.69 mM of an analyte, X, and 1.22 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 3793 and 10323, respectively. Determine the response factor for X relative to S. F = To determine the concentration of X in an unknown solution, 1.00 mL of 8.70 mM S was added to 3.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After...
A solution contains 4.96 mM of an analyte, X, and 1.81 mM of a standard, S....
A solution contains 4.96 mM of an analyte, X, and 1.81 mM of a standard, S. Upon chromatographic separation of the solution, peak areas for X and S are 3189 and 10239, respectively. Determine the response factor for X relative to S. To determine the concentration of X in an unknown solution, 1.00 mL of 8.10 mM S was added to 3.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After chromatographic separation, this...
26. Consider a solution containing 3.28 mM of an analyte, X, and 1.17 mM of a...
26. Consider a solution containing 3.28 mM of an analyte, X, and 1.17 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 3853 and 10913, respectively Determine the response factor (F) for X relative to S 0 125 0 15 03532
A standard solution containing 5.6 10-8 M iodoacetone and 2.5 10-7 M p-dichlorobenzene (an internal standard)...
A standard solution containing 5.6 10-8 M iodoacetone and 2.5 10-7 M p-dichlorobenzene (an internal standard) gave peak areas of 306 and 877, respectively, in a gas chromatogram. A 3.00 mL unknown solution of iodoacetone was treated with 0.100 mL of 1.0 10-5 M p-dichlorobenzene and the mixture was diluted to 10.00 mL. Gas chromatography gave peak areas of 685 and 329 for iodoacetone and p-dichlorobenzene, respectively. Find the concentration of iodoacetone in the 3.00 mL of original unknown.
A known mixture of Compound X (1.52 mg/mL) and Compound Y (1.73 mg/mL) gave peak areas of 16.02 and 9.41 cm², respectiv...
A known mixture of Compound X (1.52 mg/mL) and Compound Y (1.73 mg/mL) gave peak areas of 16.02 and 9.41 cm², respectively, after separation by isocratic HPLC. A solution was prepared by mixing 8.76 mg of Compound Y with 5.00 mL of unknown containing just Compound X, and diluting to 10.00 mL. Peak areas of 5.96 cm- (Compound X) and 4.86 cm (Compound Y) were measured. Find the concentration of Compound X in the unknown.
in a preliminary data, a solution containing 0.0837 M "X" and 0.0666 M internal standard give...
in a preliminary data, a solution containing 0.0837 M "X" and 0.0666 M internal standard give peak area Ax = 423 and As = 347. To analyze unknown, 10.0 mL of 0.146 internal standard were added to 10.0 mL of unknown. The mixture was diluted to 25.0 mL in volumetric flask. Final solution gave Ax = 553 and As = 582. What is [X]i ?
which mechanisit causes band broadening? ornal standard. Compounds C and D gave the fol- mum speed,...
which mechanisit causes band broadening? ornal standard. Compounds C and D gave the fol- mum speed, whic 92-18. Internal ng HPLC results: lowing HPLC Concentration (mg/mL) in mixture 1.03 1.16 Compound matograph internal st for miz 30 (a) Draw structure (b) Inte partners (c) Ra matog P eak area (cm) 10.86 4.37 (d) G peaks deute A solution was prepared by mixing 12.49 mg of D plus 10.00 mL of unknown containing just C, and diluting to 25.00 mL. Peak...
5-29. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3 473 and 10 222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was diluted to 10.0 mL This solution gave peak areas of 5 428 and 4 431 for X and S respectively (a) Calculate the response factor for the analyte (b) Find the concentration of S...
Consider a solution containing 4.69 mM of an analyte, X, and 1.22 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 3793 and 10323, respectively. Determine the response factor for X relative to S. F = To determine the concentration of X in an unknown solution, 1.00 mL of 8.70 mM S was added to 3.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After...
A solution contains 4.96 mM of an analyte, X, and 1.81 mM of a standard, S. Upon chromatographic separation of the solution, peak areas for X and S are 3189 and 10239, respectively. Determine the response factor for X relative to S. To determine the concentration of X in an unknown solution, 1.00 mL of 8.10 mM S was added to 3.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After chromatographic separation, this...
26. Consider a solution containing 3.28 mM of an analyte, X, and 1.17 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 3853 and 10913, respectively Determine the response factor (F) for X relative to S 0 125 0 15 03532
A known mixture of Compound X (1.52 mg/mL) and Compound Y (1.73 mg/mL) gave peak areas of 16.02 and 9.41 cm², respectively, after separation by isocratic HPLC. A solution was prepared by mixing 8.76 mg of Compound Y with 5.00 mL of unknown containing just Compound X, and diluting to 10.00 mL. Peak areas of 5.96 cm- (Compound X) and 4.86 cm (Compound Y) were measured. Find the concentration of Compound X in the unknown.
which mechanisit causes band broadening? ornal standard. Compounds C and D gave the fol- mum speed, whic 92-18. Internal ng HPLC results: lowing HPLC Concentration (mg/mL) in mixture 1.03 1.16 Compound matograph internal st for miz 30 (a) Draw structure (b) Inte partners (c) Ra matog P eak area (cm) 10.86 4.37 (d) G peaks deute A solution was prepared by mixing 12.49 mg of D plus 10.00 mL of unknown containing just C, and diluting to 25.00 mL. Peak...
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