Consider the following reaction at 25°C: A(g) + 2B(g) → C(g) Kc= 4.18x106
What is the value of the rate constant in terms of pressure, Kp?
Express your answer in scientific notation. KP = KC(RT)Δn
Consider the following reaction at 25°C: A(g) + 2B(g) → C(g) Kc= 4.18x106 What is the...
Consider the following reaction: A + 2B → 3 C Keq= 4.45x106 What is the value of the rate constand if the reaction is reversed? Express your answer in scientific notation. Consider the following reaction: A + 2B → 3 C Keq= 2.77x106 What is the value of the rate constant if the reaction is multipled by 2? Express your answer in scientific notation.
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. For the reaction 2A(g)+2B(g)⇌C(g) Kc = 80.2...
1. The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. Part A For the reaction 3A(g)+2B(g)⇌C(g)...
For the reaction 3A(g)+2B(g)⇌C(g) Kc = 73.0 at a temperature of 379 ∘C . Calculate the value of Kp. Express your answer numerically. For the reaction X(g)+2Y(g)⇌3Z(g) Kp = 2.82×10−2 at a temperature of 195 ∘C . Calculate the value of Kc. Express your answer numerically.
At 25°C, the equilibrium constant, for the reaction: 2 A (g) + 2B (g) <-> 3C (g) + 4D(s) If Kp = 37.1, what is the value of Kc? Please thoroughly explain each step. Thanks!
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation Kp=Kc(RT)Δn where R=0.08206 L⋅atm/(K⋅mol), T is the absolute temperature, and Δn is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N2(g)+3H2(g)⇌2NH3(g) for which Δn=2−(1+3)=−2. A) For the reaction 3A(g)+3B(g)⇌C(g) Kc =...
Be sure to answer all parts. The equilibrium constant Kc for the reaction I2(g) ⇆ 2I(g) is 3.84 × 10−5 at 724 ° C. Calculate Kc and KP for the equilibrium 2I(g) ⇆ I2(g) at the same temperature. Kc = × 10 (Enter your answer in scientific notation.) KP =
For the reaction 3A(g)+2B(g)⇌C(g) Kc = 92.6 at a temperature of 271 ∘C . Calculate the value of Kp
Part A For the reaction 3A(g)+3B(g)⇌C(g) Kc = 35.0 at a temperature of 347 ∘C . Calculate the value of Kp. Express your answer numerically. Kp = SubmitHintsMy AnswersGive UpReview Part Part B For the reaction X(g)+3Y(g)⇌3Z(g) Kp = 2.30×10−2 at a temperature of 271 ∘C . Calculate the value of Kc. Express your answer numerically. Kc = SubmitHintsMy AnswersGive UpReview Part
Consider the reaction A(g) + 2B(g) ⇌ C(g) at 25 °C. The initial pressures of all the gases are 0.100 atm. Once equilibrium has been established, it is found that Pc = 0.140 atm. What is Kp for this reaction at 25 °C. Please explain and/or show the steps.