A 4.0 kg box is on a frictionless 35° slope and is connected via a massless...
A 4.0 kg box is on a frictionless 35° slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.0 kg weight. What is the acceleration (magnitude and direction) of the 2.0 kg block as the blocks are moving?
Homework Answers
FBD of 2 kg
m2 a = m2 g - T
T = m2 g - m2 a... (i)
FBD of mass placed at slope
m1 a = T - m1 g sin x
puttinh value of T in above equation
m1 a = m2 g - m2 a - m1 g sin x
a ( m1 + m2) = m2 g - m1 g sin x
a ( 4 + 2) = 2* 9.8 - 4* 9.8* sin 35
a = 0.4807 m/s^2
directed upwards (towards the pulley)
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