Question

Experiment	Volume of acetic acid(mL)	Moles of acetic acid	mass of baking soda(g)	Moles baking soda	Total Moles	Mole fraction baking soda	Circumference(cm)	Volume of carbon dioxide(cm3)
1	24	0.419	9.02				47.5
2	21	0.366	13.01				55
3	18	0.314	17.54				60.5
4	15	0.262	22.035				66.0
5	12	0.209	26.519				63.5
6	9	0.157	31.03				56.5
7	6	0.105	35.005				52.0
8	None	None	N/A	N/A	N/A	1.00	0.00	0.00

I need to know how to calculate and fill in the blank spaces above.

Answer 1

Moles of baking soda (n) can be determined as follows.

n = mass/molar mass

Here, molar mass of baking soda (NaHCO3) = 23+1+12+(3×16) = 84 g/mol

For example, in experiment 1, n = 9.02 g/(84 g/mol) = 0.10738 mol

Total moles = moles of acetic acid + moles of baking soda = 0.419 + 0.10728 = 0.52638 mol

Molefraction of baking soda = moles of baking soda/total moles = 0.10738 mol/0.52638 mol = 0.204

Volume of carbon dioxide = 0.10738 mol×22400 cm^3/(47.5 cm)^3 = 2405.312 cm^3 (since 1 mole of any gas ay STP occupies 22.4 L = 22400 cm^3 volume).