Question

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint...

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a normal distribution with mean μ = 6 ml and standard deviation σ = 0.2 ml is a reasonable model for the distribution of the variable x = amount of red dye in the paint mixture. Use the normal distribution model to calculate the following probabilities. (Round your answers to four decimal places.)

(b) P(x < 6.2)=

(d) P(5.6 < x < 6.2) =  

(e) P(x > 5.5) =  

(f) P(x > 4.8) =

An article reported that what airline passengers like to do most on long flights is rest or sleep; in a survey of 3697 passengers, almost 70% did so. Suppose that for a particular route the actual percentage is exactly 70%, and consider randomly selecting nine passengers. Then x, the number among the selected nine who rested or slept, is a binomial random variable with n = 9 and p = 0.7. (Round your answers to four decimal places.)

(a) Calculate p(6).
p(6) =  

(b) Calculate p(9), the probability that all nine selected passengers rested or slept.
p(9) =  

(c) Determine P(x ≥ 6).
P(x ≥ 6) =

Interpret this probability.

This is the probability that exactly 6 out of 10 selected passengers rested or slept.This is the probability that at least 6 out of 10 selected passengers rested or slept.     This is the probability that exactly 6 out of 9 selected passengers rested or slept.This is the probability that at least 6 out of 9 selected passengers rested or slept.

NBC News reported that 1 in 20 children in the U.S. has a food allergy.† Consider selecting 15 children at random. Define the random variable x as

x = number of children in the sample of 15 that have a food allergy.

Find the following probabilities. (Round your answers to three decimal places.)

(a)

P(x < 2)

(b)

P(x ≤ 2)

(c)

P(x ≥ 3)

(d)

P(1 ≤ x ≤ 2)

Industrial quality control programs often include inspection of incoming materials from suppliers. If parts are purchased in large lots, a typical plan might be to select 20 parts at random from a lot and inspect them. A lot might be judged acceptable if one or fewer defective parts are found among those inspected. Otherwise, the lot is rejected and returned to the supplier. Use technology or Appendix Table 9 to find the probability of accepting lots that have each of the following. (Hint: Identify success with a defective part. Round your answers to three decimal places.)

(a)  5% defective parts
P(lot will be accepted) =  

(b)  20% defective parts
P(lot will be accepted) =  

(c)  25% defective parts
P(lot will be accepted) =


0 0
Add a comment Improve this question Transcribed image text
Answer #1



Add a comment
Know the answer?
Add Answer to:
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A camping equipment company purchases small light bulbs from another company for use in flashlights. The...

    A camping equipment company purchases small light bulbs from another company for use in flashlights. The bulbs are shipped in large lots, with several hundred bulbs in each lot. When a lot is received, a random sample of 50 of the bulbs is selected and tested to see if they are good (i.e., not burned out). If more than 3 of the bulbs in the sample fail to light up when tested, the company rejects the entire lot and returns...

  • 7. a. b. c. Assume that random guesses are made for nine multiple choice questions on...

    7. a. b. c. Assume that random guesses are made for nine multiple choice questions on an SAT test, so that there are n = 9 trials, each with probability of success (correct) given by p = 0.2. Find the indicated probability for the number of correct answers. Find the probability that the number x of correct answers is fewer than 4. P(X<4)= (Round to four decimal places as needed.) Assume that random guesses are made for 2 multiple-choice questions...

  • NBC News reported on May 2, 2013, thot 1 in 20 children in the United States...

    NBC News reported on May 2, 2013, thot 1 in 20 children in the United States have e food allergy of some sort. Consider selecting a random sample of 15 children and let X be the number in the sample who have a food allergy. Then X Bi1,.). (Round your probabilities to three decimal places.) (a) Determine both P(X S 3) and P(X 3) P(X s 3) (b) Determine P(X 4) A(X24) . () Determine P[1 sXS 3), What are...

  • NBC News reported on May 2, 2013, that 1 in 20 children in the United States...

    NBC News reported on May 2, 2013, that 1 in 20 children in the United States have a food allergy of some sort. Consider selecting a random sample of 15 children and let X be the number in the sample who have a food allergy. Then X ~ Bin(15, 0.05). (Round your probabilities to three decimal places.) (a) Determine both P(X ≤ 3) and P(X < 3). P(X ≤ 3) = P(X < 3) = (b) Determine P(X ≥ 4)....

  • A population of values has a normal distribution with μ = 221.5 and σ = 27.5...

    A population of values has a normal distribution with μ = 221.5 and σ = 27.5 . You intend to draw a random sample of size n = 160 . Find the probability that a single randomly selected value is less than 223?   P(X < 223) = Find the probability that a sample of size n=160n=160 is randomly selected with a mean less than 223. P(M < 223 Enter your answers as numbers accurate to 4 decimal places. Answers obtained...

  • A population of values has a normal distribution with u = a random sample of size...

    A population of values has a normal distribution with u = a random sample of size n = 16. 229.4 and o = 67.4. You intend to draw Find the probability that a single randomly selected value is greater than 212.6. P(X > 212.6) = Find the probability that a sample of size n = 16 is randomly selected with a mean greater than 212.6. P(M> 212.6) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained...

  • A population of values has a normal distribution with μ=152.3 and σ=54.2. You intend to draw...

    A population of values has a normal distribution with μ=152.3 and σ=54.2. You intend to draw a random sample of size n=245. Find the probability that a single randomly selected value is between 141.2 and 145.4. P(141.2 < X < 145.4) = Find the probability that a sample of size n=245 is randomly selected with a mean between 141.2 and 145.4. P(141.2 < M < 145.4) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using...

  • A population of values has a normal distribution with mean=155.9 and standard deviation=42.1. You intend to...

    A population of values has a normal distribution with mean=155.9 and standard deviation=42.1. You intend to draw a random sample of size=12. Find the probability that a single randomly selected value is less than 172.9. P(X<172.9). Find the probability that a sample of size=12 is randomly selected with a mean less than 172.9. P(M<172.9). Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

  • A population of values has a normal distribution with μ = 149.8 and σ = 25.6...

    A population of values has a normal distribution with μ = 149.8 and σ = 25.6 . You intend to draw a random sample of size n = 103 . Find the probability that a single randomly selected value is between 148.3 and 157.6. P(148.3 < X < 157.6) = 0.094 Incorrect Find the probability that a sample of size n = 103 is randomly selected with a mean between 148.3 and 157.6. P(148.3 < M < 157.6) = Incorrect...

  • A population of values has a normal distribution with μ = 161.2 and σ = 4.9...

    A population of values has a normal distribution with μ = 161.2 and σ = 4.9 . You intend to draw a random sample of size n = 220 . Find the probability that a single randomly selected value is between 160.6 and 161.8. P(160.6 < X < 161.8) = 5.184 Incorrect Find the probability that a sample of size n = 220 is randomly selected with a mean between 160.6 and 161.8. P(160.6 < M < 161.8) = .9307...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT