I need help with the following: Values= 50,27,66,55,59,45,30,41,54,46,77,37,45,39,46,54,37,57,27,45,30,34,32,54,48,45,36,37,39,37,48,34,27,37,43,28,48,36,36,55,45,36,34,50,36,45,70,34,21,46 Standard deviation= Mean= Confidence intervals with margin error.
I need help with the following:
Values= 50,27,66,55,59,45,30,41,54,46,77,37,45,39,46,54,37,57,27,45,30,34,32,54,48,45,36,37,39,37,48,34,27,37,43,28,48,36,36,55,45,36,34,50,36,45,70,34,21,46
Standard deviation=
Mean=
Confidence intervals with margin error for 70%, 80%, 85%, 90%,95%
Homework Answers
Add Answer to:
I need help with the following:
Values=
50,27,66,55,59,45,30,41,54,46,77,37,45,39,46,54,37,57,27,45,30,34,32,54,48,45,36,37,39,37,48,34,27,37,43,28,48,36,36,55,45,36,34,50,36,45,70,34,21,46
Standard deviation=
Mean=
Confidence intervals with margin error.
Given a sample mean=13.24; sample standard deviation=3.40; estimated standard error of the mean=0.567; margin of error...
Given a sample mean=13.24; sample standard deviation=3.40; estimated standard error of the mean=0.567; margin of error for 95% confidence interval for estimating the population mean=1.151. What is the upper bound of the 95% confidence interval? (Enter the value with 3 decimal places in the form ##.###)
I really need help with my Confidence Intervals for the Mean homework, can someone please help?...
I really need help with my Confidence Intervals for the Mean homework, can someone please help? 1. You measure 34 dogs' weights, and find they have a mean weight of 52 ounces. Assume the population standard deviation is 10.2 ounces. Based on this, construct a 99% confidence interval for the true population mean dog weight. Give your answers as decimals, to two places ________________ ± ______________ ounces 2. Assume that a sample is used to estimate a population mean μμ....
what is the margin of error and the confidence interval? Question Help In a random sample...
what is the margin of error and the confidence interval?
Question Help In a random sample of seven people, the mean driving distance to work was 24.7 miles and the standard deviation was 6.6 miles. Assuming the population is normally distributed and using the I-distribution, a 90% confidence interval for the population mean is (15.5, 33.9) (and the margin of error is 9.2). Through research, it has been found that the population standard deviation of driving distances to work is...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
Find the margin of error for a 95% confidence interval for estimating the population mean when...
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
Please Help I need the answers to below. Question 2: Construct a 95% confidence interval for...
Please Help I need the answers to below. Question 2: Construct a 95% confidence interval for the population mean. Assume that your data is normally distributed and σ is unknown. Include a statement that correctly interprets the confidence interval in context of the scenario. Calculations/Values Formulas/Answers Mean 72,224.34 Standard Deviation 22,644.46 n 364 Critical Value Margin of Error Lower Limit Upper Limit Question 3 construct a 99% confidence interval for the population mean. Assume that your data is normally distributed...
113 The margin of error for the 95% confidence interval of the mean fill is. 2...
113 The margin of error for the 95% confidence interval of the mean fill is. 2 A 0.48 3 B 0.41 4 C 0.36 5 D 0.32 714 As a class project, each of 280 students taking E270 is required to obtain a sample of n = 100 students and build a B 95% confidence interval for the distance travelled to the campus. The instructor thus receives 280 different interval e estimates. The instructor would expect_ ofthese intervals to capture...
Assume the population standard deviation is 45 minutes. Find (a) the point estimate of the population...
Assume the population standard deviation is 45 minutes.
Find (a) the point estimate of the population mean μ mu and
(b) the margin of error for a 90% confidence interval, and
(c) construct a 90% confidence interval for the population mean.
Pb Concentration Values (ppm)
Pb Concentration Values (ppm) 135 145 95 140 135 95 110 50 90 165 110 125 80 125 130 110 25 7565 100 60 125 115 135 9590 14040 75 50130 85 100 160 135...
Question: How can I determine the sample size given the standard error (SE <= 70), and...
Question: How can I determine the sample size
given the standard error (SE <= 70), and in the confidence
intervals of 95% and 85% using t-tables.
Side Note: I am studying for my finals and have
been asked to answer the following question but I am not completely
sure how to do so. I believe I would have to have the standard
deviation provided to answer this, but am not completely sure if
that is the case. If this does...
Determine the margin of error for a confidence interval to estimate the population mean with nequals22...
Determine the margin of error for a confidence interval to estimate the population mean with nequals22 and s = 11.6 for the confidence levels below. a) 80% b) 90% c) 99% a) The margin of error for an 80% confidence interval is nothing.
what is the margin of error and the confidence interval?
Question Help In a random sample of seven people, the mean driving distance to work was 24.7 miles and the standard deviation was 6.6 miles. Assuming the population is normally distributed and using the I-distribution, a 90% confidence interval for the population mean is (15.5, 33.9) (and the margin of error is 9.2). Through research, it has been found that the population standard deviation of driving distances to work is...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
113 The margin of error for the 95% confidence interval of the mean fill is. 2 A 0.48 3 B 0.41 4 C 0.36 5 D 0.32 714 As a class project, each of 280 students taking E270 is required to obtain a sample of n = 100 students and build a B 95% confidence interval for the distance travelled to the campus. The instructor thus receives 280 different interval e estimates. The instructor would expect_ ofthese intervals to capture...
Assume the population standard deviation is 45 minutes.
Find (a) the point estimate of the population mean μ mu and
(b) the margin of error for a 90% confidence interval, and
(c) construct a 90% confidence interval for the population mean.
Pb Concentration Values (ppm)
Pb Concentration Values (ppm) 135 145 95 140 135 95 110 50 90 165 110 125 80 125 130 110 25 7565 100 60 125 115 135 9590 14040 75 50130 85 100 160 135...
Question: How can I determine the sample size
given the standard error (SE <= 70), and in the confidence
intervals of 95% and 85% using t-tables.
Side Note: I am studying for my finals and have
been asked to answer the following question but I am not completely
sure how to do so. I believe I would have to have the standard
deviation provided to answer this, but am not completely sure if
that is the case. If this does...
Most questions answered within 3 hours.
-
Living in a group could bring several disadvantages to an
individual. What are some of the...
asked 11 minutes ago -
Complete and balance the following reactions. In case of no
reaction occurring write NR.
Mix #1:...
asked 16 minutes ago -
If an economy consumes 75% of any increase in income, then an
increase in autonomous investment...
asked 19 minutes ago -
A shotputter throws the shot with an initial speed of 15.8 m/s
at a 38.0 ∘...
asked 35 minutes ago -
Debra and Merina sell electronic equipment and supplies through
their partnership. They wish to expand their...
asked 36 minutes ago -
How does a linear regression allow you to better estimate
trends, costs, and other factors in...
asked 44 minutes ago -
1. (15%) Describe the difference between a pull (Kanban), push
and CONWIP production systems.
asked 40 minutes ago -
QUESTION 5
The total area under the Z distribution curve is equal to:
a.
10
b....
asked 49 minutes ago -
Using Python
The variables x and y refer to numbers. Write a code segment
that prompts...
asked 1 hour ago -
If
the coefficient of static friction between a box and the floor is
0.35 with what...
asked 1 hour ago -
A die is designed to punch holes with a radius of 1.08 10-2 m in
a...
asked 1 hour ago -
government can increase import through
a. export subsidies
b. tax breaks
c. increase import tax
d....
asked 1 hour ago