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Which of the following is the correct way to code a try statement that displays the...

Which of the following is the correct way to code a try statement that displays the type and message of the exception that’s caught?

try:

number = int(input("Enter a number: "))

print("Your number is: ", number)

except Exception as e:

print(e(type), e(message))

try:

number = int(input("Enter a number: "))

print("Your number is: ", number)

except Exception as e:

print(type(e), e)

try:

number = int(input("Enter a number: "))

print("Your number is: ", number)

except Exception:

print(Exception(type), Exception(message))

try:

number = int(input("Enter a number: "))

print("Your number is: ", number)

except Exception:

print(type(Exception), Exception)

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Answer #1

try:

number = int(input("Enter a number: "))   
print("Your number is: ", number)

except Exception as e:

print(type(e), e)

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