Hello I have a couple questions
A distribution of raw scores with respect to x has a mean (x̅ x) of 55 and a standard deviation (sx) of 4. Convert a raw score (x) of 50 into a z score from this distribution. zx =
a. 1 b. -1.25 c. 1.25 d. -2.50 e. 2.50
2. With respect to any distribution of standard scores (a
non-normal or a normal distribution of z scores), the mean of the
distribution is equal to 0 and the standard deviation of the
distribution is equal to 1.
a. true
b. false
1.
the PDF of normal distribution is = 1/σ * √2π * e ^ -(x-u)^2/
2σ^2
standard normal distribution is a normal distribution with a,
mean of 0,
standard deviation of 1
equation of the normal curve is ( Z )= x - u / sd ~ N(0,1)
mean ( u ) = 55
standard Deviation ( sd )= 4
sample mean x =50
Z score = 50-55/4
Z score = -1.25
Answer:
Z score =-1.25
option:B
2.
True
With respect to any distribution of standard scores (a non-normal
or a normal distribution of z scores)
option:A
the PDF of normal distribution is = 1/σ * √2π * e ^ -(x-u)^2/
2σ^2
standard normal distribution is a normal distribution with a,
mean of 0,
standard deviation of 1
equation of the normal curve is ( Z )= x - u / sd ~ N(0,1)
mean ( u ) = 0
standard Deviation ( sd )= 1
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