A school district is trying to decrease the uncertainty concerning pick-up times on a particular school bus route. Due to uncertainty in traffic patterns, the school district examines two alternative routes. In a sample of 15 days on alternative route #1, the average driving time for the school bus is 40 minutes with a standard deviation of 15 minutes. In a sample of 16 days using alternative route #2, the average drive time is 44 minutes with a standard deviation of 11 minutes.
At the 5% level of significance, is there a difference between the driving times of the two bus routes. Show all work on how you come to your conclusion and provide a clear explanation as if you were explaining the results to the school district.
Solution
The solution is based on two-sample t-test.
Let X = pick-up time (minutes)in route #1
Y = pick-up time (minutes)in route #2
Let mean and standard deviation of X be respectively µ1 and σ1 and those of Y be µ2 andσ2, where σ12 = σ22 = σ2, say and σ2 is unknown.
Hypotheses:
Null: H0: µ1 = µ2 Vs Alternative: HA: µ1 ≠ µ2
Test Statistic:
t = (Xbar - Ybar)/[s√{(1/n1) + (1/n2)}]
where
s2 = {(n1 – 1)s12 + (n2 – 1)s22}/(n1 + n2 – 2);
Xbar and Ybar are sample averages and
s1,s2 are sample standard deviations based on n1 observations on X and n2 observations on Y respectively.
Calculations
Summary of Excel calculations is given below:
n1 |
15 |
n2 |
16 |
Xbar |
40 |
Ybar |
44 |
s1 |
15 |
s2 |
11 |
s2 |
171.2069 |
s |
13.08461 |
tcal |
0.850598 |
α |
0.05 |
tcrit |
2.04523 |
p-value |
0.401962 |
(n1 + n2 - 2) |
29 |
2α |
0.1 |
n1 -1 |
14 |
n2 -1 |
15 |
s12 |
225 |
s22 |
121 |
(n1 - 1)s12 |
3150 |
(n2 - 1)s22 |
1815 |
sum |
4965 |
n1 + n2-2 |
29 |
1/n1 |
0.066667 |
1/n2 |
0.0625 |
sum |
0.129167 |
sqrt |
0.359398 |
s.sqrt (SE) |
4.702576 |
Distribution, Significance Level, α Critical Value and p-value:
Under H0, t ~ tn1 + n2 - 2. Hence, for level of significance α%,
Critical Value = upper (α/2)% point of tn1 + n2 - 2 and
p-value = P(tn1 + n2 - 2 > | tcal |)
Using Excel Function: Statistical TINV andTDIST, these are found to be as shown in the above table.
Decision:
Since | tcal | < tcrit, or equivalently since p-value > α, H0 is accepted.
Conclusion:
There is not sufficient evidence to suggest that the mean pick-up times differ.
Hence, conclude that
there is no difference between the driving times of the two bus routes. Answer 1
DONE
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