Consider reaction (1) shown below with it's associated equilibrium constant. What is the equilibrium constant for reaction (2)?
Report your answer to THREE significant figures.
(1) 3 A + 3 B ⇌ 3 C , K = 0.464
(2) 3 C ⇌ 3 A + 3 B , K = ??
(1). 3A + 3B 3C for this reaction K = 0.464
expression for K = [C]3/[A]3 [B]3 = 0.464. ...... (1)
(2) 3C 3A + 3B.
expression of K for this reaction is
K = [A]3 [B]3/ [C]3 which is reverse of (1)
K = 1/0.464 = 2.16
thus we calculated K of second reaction which is just reverse of (1).
Consider reaction (1) shown below with it's associated equilibrium constant. What is the equilibrium constant for...
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