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Identify the compound with the lowest boiling point. A) CH3OCH3 B) CH3CH2CH3 C) CH3CHO D) (CH3)2O...

Identify the compound with the lowest boiling point.

A) CH3OCH3 B) CH3CH2CH3 C) CH3CHO D) (CH3)2O E) CH3CN

* I need help understanding why the answer is B, when E has a lower molar mass. Also, I was under the impression that linear molecules such as B, have increased dispersion forces, and would ultimately have a higher boiling point.

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Answer #1

we know that intermolecular forces strength order :

hydrogen bond > dipole -dipole > ion-dipole > dispersion forces

if intermolecular force strength increases boiling point increases .

now coming to that point.

A) CH3-O-CH3 . here C and O electronegaitivity is different . so there will be partial positive charge on C and partially negative charge on O will be formed . so it is dipole . intermolecular force is also dipole-dipole forces

like wise C) D) E ) all are also have dipole -dipole forces. except B)

B has only dispersion forces these are very weak forces. so readily evoporates into gas . so lesser boiling point for B)

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