Question

Please calculate the kcat/Km and k (with correct units) for P1 and P2.

Aldehyde Dehydrogenase	P1 (person 1)	P2 (person 2)
kcat (s^-1)	6	0.3
Km (M)	0.0002	0.006
kcat/Km	?	?
k	?	?
[S] (M)	0.002	0.002

Answer 1

Sol :-

Aldehyde Dehydrogenase	P1 (person 1)	P2 (person 2)
kcat (s^-1)	6	0.3
Km (M)	0.0002	0.006
kcat/Km	30000 M-1s-1	50 M-1s-1
k	?	?
[S] (M)	0.002	0.002

Explanation :-

P1(Person 1) :-

Given,

k_cat = 6.0 s^-1 and

K_m = 0.0002 M

Therefore,

k_cat /k_m = 6.0 s^-1 /0.0002 M

= 30000 M^-1s^-1

-----------------------------------------------

P2(Person 2) :-

Given,

k_cat = 0.3 s^-1 and

K_m = 0.006 M

Therefore,

k_cat /k_m = 0.3 s^-1 /0.006 M

= 50 M^-1s^-1

Value of k can be determine with experimental data which is not given.