Please calculate the kcat/Km and k with correct units for person 1 (P1) and person 2...
Please calculate the kcat/Km and k with correct units for person 1 (P1) and person 2 (P2). Use the Michaelis-Menten Equation
| Aldehyde Dehydrogenase | Person 1 | Person 2 |
| kcat (S-1) | 6.0 | 0.3 |
| Km (M) | 0.0002 | 0.006 |
| Kcat/Km | ? | ? |
| k | ? | ? |
| [S] (M) | 0.002 | 0.002 |
Homework Answers
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Please calculate the kcat/Km and k with correct units for person
1 (P1) and person 2...
Please calculate the kcat/Km and k (with correct units) for P1 and P2. Aldehyde Dehydrogenase P1...
Please calculate the kcat/Km and k (with correct units) for P1 and P2. Aldehyde Dehydrogenase P1 (person 1) P2 (person 2) kcat (s^-1) 6 0.3 Km (M) 0.0002 0.006 kcat/Km ? ? k ? ? [S] (M) 0.002 0.002
IAt p6, carbonic anhydrase has a keue of 60,000s'. please estimate the ku, if the phf is 13 incre...
iAt p6, carbonic anhydrase has a keue of 60,000s'. please estimate the ku, if the phf is 13 increased to 7.0. Please justify your answer. Co,+ H20H2CO 14. The two person have the same k after drinking alcohol. Please calculate the substrate earbonie enhydrase concentration in Person 1. Please justify your answer. Person 1 Aldehyde koolS') Km (M) erson 2 dehydrogenase 0.0002 0.006 0.002 15. There is a tyrosine protease, which uses similar mechanism to a cysteine protease. Write down...
1. Show, using the Michaelis-Menten equation, that when [S] >>> Km, vo = Vmax. Show, using...
1. Show, using the Michaelis-Menten equation, that when [S] >>> Km, vo = Vmax. Show, using the M-M equation that when [S] <<<Km, vo =[S][Et]kcat/Km. 2. What is Vmax? Provide both a mathematical and written description of Vmax? How can Vmax be experimentally altered? How can we use Vmax to determine the turnover number (kcat) of an enzyme-catalyzed reaction? What is the major challenge of determining Vmax from an Michaelis-Menten plot?
Kcat =30.0 s-1 Km= 0.005 M Operating at 1/4 Vmax What is [S] ? The solutions...
Kcat =30.0 s-1
Km= 0.005 M
Operating at 1/4 Vmax
What is [S] ?
The solutions manuel doesn't explain the problem well. Whete
does the 0.33 km come from?
For part 2 : Plug in [S]= 1/2 Km, 2 Km, and 10 Km
Where does the 1.5 Km come from?
Answer (a) Here we want to find the value of [S] when Vo = 0.25 V max. The Michaelis-Menten equation is V = Vmax[S]/(Km + [SD so V = Vmax...
Please show how to calculate Km and Vmax for no inhibitor/low inhibitor given graph. Show how to ...
Please show how to calculate Km and Vmax for no inhibitor/low
inhibitor given graph. Show how to solve for a.,a/a etc.
Lineweaver Burk #4: No inhibitor, Low inhibitor 0.2 ▲ No inhibitor Low inhibitor 0.15 0.05 0.2 0.15 0.1 0.05 0.05 0.1 0.15 02 5 1/IS] in units of 1/mM Fill in the blanks. Show your work. No inhibitor Kmno Vmax,o- Vmax,w = ๙ Vmax,o Solve for ๙ inhibitor Krmkw =픕Km,o Solve for 픕 Hint treat, as a single number....
D-Lactose is the substrate for B-galactosidase. Given Vo = kcat [Et] [S]/km + [S], calculate [S],...
D-Lactose is the substrate for B-galactosidase. Given Vo = kcat [Et] [S]/km + [S], calculate [S], when Km = 4.0 nM, V. = 10.5 M s', kcat = 500 s, and [Et] = 40 uM Calculate the catalytic efficiency. Below is a double-reciprocal plot for an enzyme reaction in the absence and presence of of inhibitor. Give the equation for the line. Calculate Vmax and Km for the enzyme and enzyme plus inhibitor. Which type of inhibition is apparent. 0.10...
1. According to the Michaelis-Menten equation, when is the reaction velocity at half the maximal value...
1. According to the Michaelis-Menten equation, when is the reaction velocity at half the maximal value (vo = 0.5 Vmax) A. when [S] = 0.5 Km B. when [S] = 1.0 Km C. when vo = kcat [E] D. when vo = kcat / Km 2. The value of Vmax depends on ... A. k1 and k-1 B. k1 and k2 C. k1 only D. k2 only 3. When is Km approximately equal to Kd? A. when k1 is much...
HUUR UUU UUILUUITUL LUIUILINU 2 PV, 10 pul, posta 10. Applying the Michaelis-Menten Equation II An...
HUUR UUU UUILUUITUL LUIUILINU 2 PV, 10 pul, posta 10. Applying the Michaelis-Menten Equation II An en- zyme catalyzes the reaction M = N. The enzyme is present at a concentration of 1 nm, and the Vmax is 2 um s-1. The Kn for substrate M is 4 um. (a) Calculate kcat. (b) What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 2.0?
16. Use the Michaelis-Menten graph to estimate Va and Ku. Show the units. Use the Lineweaver...
16. Use the Michaelis-Menten graph to estimate Va and Ku. Show the units. Use the Lineweaver Burk graph, the equation for the line is y = 0.3017x + 0.0987, to calculate and Ku. Show the units. Views : 5 5 V, M/S Ku= 2. 2m 0 5 10 15 20 25 [S], M Venu= 10.1m/ms y = 0.3017x + 0.0987 1/ vs/M km = _A4 2.10 MM 1/[5), M AN
Estimation of Vmax and K by Inspection Although graphical methods are available for accurate determination of...
Estimation of Vmax and K by Inspection Although graphical methods are available for accurate determination of the Vmax and K of an enzyme-catalyzed reaction (see Box 6-1), sometimes these quantities can be quickly estimated by inspecting values of Vat increasing (Sl. Estimate the Vmax and Km of the enzyme-catalyzed reaction for which the following data were obtained. V (pm/min) V (m/min) 112 [S] (M) 2.5 x 10 4.0 x 100 1 x 10-5 2 x 10-5 [S(M) 4 x 10-5...
iAt p6, carbonic anhydrase has a keue of 60,000s'. please estimate the ku, if the phf is 13 increased to 7.0. Please justify your answer. Co,+ H20H2CO 14. The two person have the same k after drinking alcohol. Please calculate the substrate earbonie enhydrase concentration in Person 1. Please justify your answer. Person 1 Aldehyde koolS') Km (M) erson 2 dehydrogenase 0.0002 0.006 0.002 15. There is a tyrosine protease, which uses similar mechanism to a cysteine protease. Write down...
Kcat =30.0 s-1
Km= 0.005 M
Operating at 1/4 Vmax
What is [S] ?
The solutions manuel doesn't explain the problem well. Whete
does the 0.33 km come from?
For part 2 : Plug in [S]= 1/2 Km, 2 Km, and 10 Km
Where does the 1.5 Km come from?
Answer (a) Here we want to find the value of [S] when Vo = 0.25 V max. The Michaelis-Menten equation is V = Vmax[S]/(Km + [SD so V = Vmax...
Please show how to calculate Km and Vmax for no inhibitor/low
inhibitor given graph. Show how to solve for a.,a/a etc.
Lineweaver Burk #4: No inhibitor, Low inhibitor 0.2 ▲ No inhibitor Low inhibitor 0.15 0.05 0.2 0.15 0.1 0.05 0.05 0.1 0.15 02 5 1/IS] in units of 1/mM Fill in the blanks. Show your work. No inhibitor Kmno Vmax,o- Vmax,w = ๙ Vmax,o Solve for ๙ inhibitor Krmkw =픕Km,o Solve for 픕 Hint treat, as a single number....
D-Lactose is the substrate for B-galactosidase. Given Vo = kcat [Et] [S]/km + [S], calculate [S], when Km = 4.0 nM, V. = 10.5 M s', kcat = 500 s, and [Et] = 40 uM Calculate the catalytic efficiency. Below is a double-reciprocal plot for an enzyme reaction in the absence and presence of of inhibitor. Give the equation for the line. Calculate Vmax and Km for the enzyme and enzyme plus inhibitor. Which type of inhibition is apparent. 0.10...
HUUR UUU UUILUUITUL LUIUILINU 2 PV, 10 pul, posta 10. Applying the Michaelis-Menten Equation II An en- zyme catalyzes the reaction M = N. The enzyme is present at a concentration of 1 nm, and the Vmax is 2 um s-1. The Kn for substrate M is 4 um. (a) Calculate kcat. (b) What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 2.0?
16. Use the Michaelis-Menten graph to estimate Va and Ku. Show the units. Use the Lineweaver Burk graph, the equation for the line is y = 0.3017x + 0.0987, to calculate and Ku. Show the units. Views : 5 5 V, M/S Ku= 2. 2m 0 5 10 15 20 25 [S], M Venu= 10.1m/ms y = 0.3017x + 0.0987 1/ vs/M km = _A4 2.10 MM 1/[5), M AN
Estimation of Vmax and K by Inspection Although graphical methods are available for accurate determination of the Vmax and K of an enzyme-catalyzed reaction (see Box 6-1), sometimes these quantities can be quickly estimated by inspecting values of Vat increasing (Sl. Estimate the Vmax and Km of the enzyme-catalyzed reaction for which the following data were obtained. V (pm/min) V (m/min) 112 [S] (M) 2.5 x 10 4.0 x 100 1 x 10-5 2 x 10-5 [S(M) 4 x 10-5...
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