Please show how to calculate Km and Vmax for no inhibitor/low inhibitor given graph. Show how to solve for a.,a/a etc.
Please show how to calculate Km and Vmax for no inhibitor/low inhibitor given graph. Show how to ...
How can the Michaelis-Menten constant, be derived from this Lineweaver-Burk plot? Vmax O km = (-1)/(x-intercept) O km = (-1) * (x-intercept) O km = 1/(x-intercept) 0 Km = s;lope
a. what are the values of Vmax and Km in the abscence if the inhibitor what are the values of Vmax and Km in the presence of the inhibitor? b. what type of inhibition is it? c. what is the dissociation constant (Ki) of the inhibition? ***d. graph a linear scatter plot including equation. Homework (CHE 407) The initial velocity for an enzyme-catalyzed reaction is measured at various initial substrate concentration [S]o, in the absence and in the presence of...
12. From the Lineweaver-Burk graph given: a. What are the Km and Vmax for the uninhibited case? b. What type of inhibition is occurring? c. Shown on the page after the Lineweaver-Burk plot are semi-qualitative sketches for three V vs. (S) plots. Which one of these most likely corresponds to this particular experiment (A,B or C)? Scani explain th Cant catimer IIIIIIIII IIIIIIIII - -- | - | IIIII We were unable to transcribe this image
please graph all 3 lines and explain the vmax&km How to: Lineweaver Burke 1. The following data was determined for an enzyme in the absence of an inhibitor and in the presence of two different inhibitors (V2 and V3). Determine the V. and K for the enzyme (1) Plot the data and determine the type of inhibition for each inhibitor (S) mm 1 V2 4.3 5.5 V1 12 20 29 2 relliate 150b
Nobody has been able to solve the Km. The Vmax values are correct. I believe I have my graph wrong. Can someone please help me solve this. Using the Lineweaver-Burk Equation 1/Vo Km/Vmax[S]1/Vmax) create a graph of both the Non-Inhibited data and Inhibited data below (on the same graph axes) and calculate the KM and VMax for each line. Vo (umol/L.min) Vo (Hmol/L-min) [Sol (umol/L) Non-Inhibited Data Inhibited Data .00e-06 13.9 7.60 .00e-06 18.0 9.90 ..10e- 05 10e-05 26.0 14.8...
show work please! with inhibitor (umoles/min/mg) [S] (mm) v- no inhibitor (umoles/min/mg) V - with inhibitor (umoles 3.0 2.29 x 103 1.83 x 103 5.0 or ble 3.20 x 103 Boristeder s obre o 2.56 x 103 7.0 3.86 x 103 USD 3.09 x 103 0 9. 4 .36 x 100W 3.49 x 103 0 11. 4 .75 x 108 3.80 x 103 Draw Lineweaver-Burk plots for the enzyme data shown above. When present, I = 0.200 m a) What...
how we can solve q2 2. a) The Michaelis-Menten mechanism is +KTERE] - @s→Es (rateco nstant kl) ク ES→ E + S (rate constant k2) E S ES-XⓟHE) orate constant k3) So d[PVdt- k3[ES] Use the steady state approximation to show [El/[ES] (k2+k3)/(k1[S] b) let Km=(k2+k3)/kl and show that you get the expression ·J [EVIES]-Km/[S] c) We will talk in class about how this information eventually gives rise the expression d[P]/dt-k3E][S/(Km +IS) Usually [S>>Km. Show what this equation simplifies to...
2.) a. Given the following equation and using the Lineweaver-Burk equation find the Vmax and Km O y=7x+2.5 for enzyme A (in mM and s). b. Suppose you want to compare similar enzymes A (above Kcat=500) with enzyme B (Km=2.0, Kcat=450) to find out which enzyme has a higher catalytic efficiency; which enzyme has the higher catalytic efficiency?
Please show work and answer. my professor gave this hint to us to solve the problem. He also said that I could find the relationship between S and Km and substitute that into the Michaelis-Menten equation. 6. The Km of RBC GLUT1 for glucose is 18 mg/dL while the Km for liver GLUT2 is 360 mg/dL. At a blood glucose concentration of 60 mg/dL, GLUT1 and GLUT2 are working at what percentage of their Vmax? A. GLUT1 at 75% Vmax...
ssessable tutorial que 03/2018 The conversion of corn starch to dextrose using the enzyme glucoamylase was studied in a batch reactor at 60°C. The initial concentration of corn starch was 25 gl. The dosage of glucoamylase, Eo, was 11.6 mgL-. Figure 1, below, shows a Lineweaver-Burk plot for results obtained for the starch to dextrose enzymatic process. 0.13 0.12 0.11 0.10 Slope of plot 1.1 hr y-intercept of plot-0.033 hr L/g 0.09 0.08 0.07 0.04 0.05 0.06 0.07 0.08 0.09...