Question

please graph all 3 lines and explain the vmax&km

How to: Lineweaver Burke 1. The following data was determined for an enzyme in the absence of an inhibitor and in the presence of two different inhibitors (V2 and V3). Determine the V. and K for the enzyme (1) Plot the data and determine the type of inhibition for each inhibitor (S) mm 1 V2 4.3 5.5 V1 12 20 29 2 relliate 150b

Answer 1

[s]	V1	V2	V3	1/[s]	1/V1	1/V2	1/V3
1	12	4.3	5.5	1	0.083333	0.23255814	0.181818182
2	20	8	9	0.5	0.05	0.125	0.1111111111
4	29	14	13	0.25	0.0344827586	0.0714285714	0.0769230769
8	35	21	16	0.125	0.0285714286	0.0476190476	0.0625
12	40	26	18	0.083333	0.025	0.0384615385	0.0555555556

0.083333 0.23255814 0.181818182 0.05 0.125 0.1111111111 0.25 0.03448275862 10.0714285714 10.0769230769 0.125 0.0285714286 10.0476190476 0.0625 0.083333 0.025 0.0384615385 10.0555555556

0.1 11 0.2 0.3 04 | 0.5 0.6 0.7 0.8 0.9 -0.1

Yı-mx, + b STATISTICS r2 = 0.9984 r=0.9992 RESIDUALS e plot PARAMETERS m= 0.0631953 b=0.0195259 y2-mx, + b STATISTICS r2 = 0.9998 r=0.9999 PARAMETERS m=0.211842 RESIDUALS e plot b=0.020042 Y3-mx, + b STATISTICS r2 = 0.9994 r=0.9997 RESIDUALS e plot PARAMETERS m=0.137221 b=0.0438366

For Graph,

Orange - 1/V1

Purple -1/V2

Blue - 1/V3

Intercept = 1/Vmax. Then Vmax = 1/intercept.=1/b

For V1, Vmax = 1/0.0195259 = 51.214028 V

For V2, Vmax = 1/0.020042 = 49.89522 V

For V3, Vmax = 1/0.0438366 = 22.811988V

Slope = km/Vmax => km = Slope x Vmax=m x Vmax

For Without inhibitor, km = 0.0631953 x 51.214028 = 3.236485

For inhibitor A, km = 0.211842 x 49.89522 = 10.56990

For inhibitor B, km = 0.137221 x 22.811988 = 3.130283

V2 and V3 are competitive inhibitor. The reason is that the two curves intersect at a point and the slopes are different.