Question

Nobody has been able to solve the Km. The Vmax values are correct. I believe I have my graph wrong. Can someone please help me solve this.

Using the Lineweaver-Burk Equation 1/Vo Km/Vmax[S]1/Vmax) create a graph of both the Non-Inhibited data and Inhibited data below (on the same graph axes) and calculate the KM and VMax for each line. Vo (umol/L.min) Vo (Hmol/L-min) [Sol (umol/L) Non-Inhibited Data Inhibited Data .00e-06 13.9 7.60 .00e-06 18.0 9.90 ..10e- 05 10e-05 26.0 14.8 37,3 26. 37.3 ,10e-05 44 0 What is the KM of the Non-inhibited data?? 9.90e-6 What the VMay for the Non-inhibited data? 49.5 the KM of the Inhibited data?? What 1,63e-5 What is the VMay for the Inhibited data? 40.7 What type of inhibition is shown by your graph? Competitive

Answer 1

As PEL THE LINE WEAVEE BUEK EaUATI6N max ser - So of data TrMI6ITED km x 4-6D e-06 49 X400 e- 06 xu9 T Km 13 9 4.00 er 06 x49. S Km 0 O7194 + 0.02.02 02 oO92142 x u.00e-0 xu9 T 1g 24 e-06 ArN I 1enE Similary b Set- af dela xl G + 49.3 6 OTD e-06 x 49.5 km Km 49: X600 e-06 007す 5T 22 499 e-o6 C data WN INH ITED o faset lay XI10e-s 49 32 km 26 0 Km 31.942 e-06

St-TD u9 S 3 10 e -or 161TE NTN ot data et Smilary f 9.10 e-03 49-5 191. 46 2 e06 KA valures Treduaug are here ue yes eseh yeacten rinereasieg fo fr InWbited data Km Oaact Yeat be Calenkatsd can Set Same h.00e-06 X40.7 ekm Set I 443 7-6 Km 28.8 X10-6 sl Set Km 30. 666 X 10-6 Set 6 Km 4 249 x1D Set -6 Kmt9, 341 x ID set 192.952 X16-6 Km-