a 1500 kg car using its brakes on a flat road needs to have an acceleration magnitude of 3 m/s2 what coefficient of friction is the minimum to make this happen
acceleration = 3 m/s2
acceleration on a rough road = ug
where u = coefficient of friction
g = acceleration due to gravity
3 = u*9.8
u = 0.306
so the coefficient of friction required = 0.306
a 1500 kg car using its brakes on a flat road needs to have an acceleration...
A 1500-\rm kg car drives at 30 \rm m/s around a flat circular track 300 \rm m in diameter. What are the magnitude and direction of the net force on the car? 9000N Since the net force is equivalent to the force of static friction, your answer to Part D is the magnitude f_s. Based on this value, what is the minimum coefficient mu_s of static friction between the road and the car?
N5M.14 Anti lock brakes keep a cars tires from skiddinh on a road
surface. A certain 1500. -kg car equipped with such brakes And
initially traveling at 27.0 m/s is able to come to rest within a
time interval of 6.00 s a) What is the minimum coefficient of
static's friction between tired and the road in this case? b) how
fat differs the car travel before it stops?
NSM.14 Anti-lock brakes keep a car's tires from skidding on a...
A car has a mass of 1500 kg. If the driver applies the brakes while on a gravel road, the maximum friction force that the tires can provide without skidding is about 7000 N. If the car is moving at 22 m/s, what is the shortest distance in which the car can stop safely?
A car has a mass of 1500 kg. If the driver applies the brakes while on a gravel road, the maximum friction force that the tires can provide without skidding is about 7000 N Part A If the car is moving at 25 m/s, what is the shortest distance in which the car can stop safely? Express your answer with the appropriate units. ? Value Units
It requires a stopping distance of 150 m to brake on a flat road from a speed of 22 m/s to rest with a particular set of brakes. (a) Find the acceleration of the car. (b) Find the coefficient of friction between the tires and the road. (You may assume the car has a mass of 1250 kg but that is NOT needed to solve the problem.)
4. A car with a mass of 1500 kg moves along a level road with an initial speed of 20 m/s. If the puts on his brakes and slides to a stop with a friction force of 3000N, How far will it take him to stop? Sketch a diagram of the situation.
gth of the Cirrl 1. A 1300 kg car moving on a flat, horizontal road negotiates a curve as shown in figure. If the radius of the curve is 40 m and the coefficient of static friction between the tires and dry pavement is 0.6, find the maximum speed the car can have and still make the turn successfully.
A 900 kg car passes a bend on a flat road with a radius of 60 m at a rate of 60 km / hour. Will the car be able to pass that bend, or will it slip if: (a) the road is dry and the coefficient of static friction is μS = 0.65; (b) ice road and μS = 0.3?
A 700 kg car is coasting along a level road, slowing down at an acceleration of 7.11 m/s^2 until coming to a stop. What is the minimum coefficient of friction between tires and roadway if this is to be possible? Assume the wheels are not locked, in which case we are dealing with static friction -- there's no sliding.
A car is travelling at 20m/s on a horizontal road. The brakes suddenly are applied and the car skids to a stop in 40 s with a constant acceleration. a) Draw a free body diagram for the car? b) Write newton's second law in the vector form and project it on the reference system. c) What is the coefficient of kinetic friction between the tires and road?