Let X be Gaussian with zero mean and unit variance. Let Y = |X|. Find:
a) The PDF fY (y)
b) The mean E[Y ]
c) Here X is uniform in (0, 1), but now you are asked to find a functiong(·) such that the PDF of Y = g(X) is
?2y 0≤y<1fY (y) = 0 otherwise
a)
We are given that X ~ N(0,1) and Y = |X|.
We need to find the pdf of Y.
First we find the cdf of Y:
Now, to find the pdf of Y, we just differentiate the cdf w.r.t.
y. Thus, we get:
b)
c)
For , the pdf of Y is given by:
Thus, for , the cdf of Y is given by:
Thus,
which is the required function.
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