Q 5-8 Your company produces electronic connectors, which consist
of a metal strip with multiple prongs assembled into a plastic
housing. The manufacturing process is divided into four separate
departments: 1) Injection molding, where the small plastic housings
are produced; 2) Stamping, where the steel strips are punched out
of thin coils of steel; 3) Plating, where the steel strips, after
being stamped, are plated with tin or gold; and 4) Assembly, where
the plated strips are inserted into the plastic housing.
The injection molding machines together have the capacity to
produce 4000 plastic housing per hour. The firm's stamping presses
can punch out 3000 steel strips per hour. The plating department
has two dedicated lines—one for tin-plating and the other for the
slower gold-plating process. The tin-plating line has a capacity of
2000 units per hour; the gold-plating line has a capacity of 500
units per hour. In the assembly department, there are six automated
assembly machines, each with the capacity to assemble 400
connectors per hour.
Assume that machines never break down, and assume that there is
sufficient plastic and steel raw material so that raw material
availability never constrains the process. Assume that the plant is
only running the tin-plated product—the gold-plating line is
completely idle.
Q1: Assume that hourly demand during work hours for tin-plated connectors is 2200 units/hr and demand for gold-plated connectors is 600 units/hr, and that both processes are active. The plant runs for 8 hours/day, 5 days/week, 50 weeks/yr. Both connector types earn a margin of $0.10 apiece. The plant is considering investing in an additional automated assembly machine, which costs $400,000. What is the payback period for this investment (in years)?
Answer: Payback period = 5 years.
5 years will be the pay back period for investing $400000/- in getting a new automated assembly machine which will increase the connector capacity by 400 units/hour.
The current capacity is = capacity of unit machine * total machines = 400*6 = 2400 nos.
The additional machine will increase the capacity by 400 units. So total capacity will be = 2400+400=2800 nos.
The payback period is calculated as below
New Machine Investment | Increase Units /hr | Daily Capacity Increase @ 8 hours/day | Weekly Capacity Increase @ 5 days/week | Yearly Capacity Increase @ 50 weeks/Year | Margin per piece | Total Yearly Margin Increase | Investment | Payback Period = Investment / yearly increased margin |
Capacity increase by additional automated assembly machine | 400 | 3200 | 16000 | 800000 | $ 0.1 | $ 80,000 | $400,000 | $ 400000 / $80000 = 5 Years |
Q 5-8 Your company produces electronic connectors, which consist of a metal strip with multiple prongs...
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