Formal Oxidation Numbers Assign formal oxidation numbers to the specified atoms in the following compounds, according...
Formal Oxidation Numbers Assign formal oxidation numbers to the specified atoms in the following compounds, according to convention. The O atom in Na2SO4 The P atom in Na3PO4 The S atom in Na2SO4 The H atom in NH3 1pts Tries 0/5 The O atom in H2SO3 The N atom in NO The P atom in H2PO3- The O atom in CuSO4
Homework Answers
O atom in Na2SO4 :-2
reason: Oxygen has an oxidation state of -2 except when it is in a peroxide like H2O2. When oxygen is in a peroxide, its oxidation state is -1
P atom in Na3PO4 :+5
reason:since 3Na is +3 and 4O is -8, P must be +5
S atom in Na2SO4:+6
reason:since 2Na is +2 and 4O is -8, P must be +6
H atom in NH3:-3
reason:3H is +3 ,N must be -3
O atom in H2SO3:-2
reason: Oxygen has an oxidation state of -2 except when it is in a peroxide like H2O2. When oxygen is in a peroxide, its oxidation state is -1
N atom in NO :+2
reason:O is -2,N must be +2
P atom in H2PO3- +3
reason: 2H is+2 and 3O is -6 and one negatve charge is +1 then P must be +3
O atom in CuSO4 :-2
reason:Oxygen has an oxidation state of -2 except when it is in a peroxide like H2O2. When oxygen is in a peroxide, its oxidation state is -1
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