Question

Does any solid silver chromate form when 2.7x10-5 g of silver nitrate is dissolved in 15.0ml of 4.0x10-4 M potassium chromate?

Answer 1

Number of moles of AgNO3 dissolved= 2.7 ×10^-5g/ 169.88g/mol = 1.59×10^-7mol

number of Ag⁺ dissolved = 1.59×10^-7mol

Volume of solution = 15ml

[Ag⁺] = (1.59 ×10^-7mol/15ml) ×1000ml = 1.06×10^-5M

[CrO4^2-] = 4.0 ×10^-4M

Ag2CrO4(s) <--------> 2Ag⁺(aq) + CrO4^2-(aq)

K_sp = [Ag⁺]²[CrO4^2-] = 1.10 ×10^-12

Qsp = [Ag⁺]²[CrO4^2-]

Qsp = (1.06 ×10^-5M )² × 4.0 ×10^-4M

Qsp = 4.49 × 10^-14

Qsp < Ksp

Therefore

Solid silver chromate would not form