Suppose 2.11 g of barium nitrate is dissolved in 50. mL of a 0.20 M aqueous solution of sodium chromate.
Calculate the final molarity of nitrate anion in the solution. You can assume the volume of the solution doesn't change when the barium nitrate is dissolved in it.
Round your answer to 2 significant digits.
Moles of barium nitrate = ( mass /molar mass)
= (2.11/261.32)
= 0.008.
Volume of solution = 50 mL = 5 × 10-3 L
Ba(NO3)2 (aq) + Na2CrO4 (aq) BaCrO4 (s) + 2 NaNO3 (aq)
So, moles of nitrate ion = 2 × moles of Barium nitrate
= 2× 0.008
= 0.016.
Molarity of nitrate ion
= ( 0.016/5×10-3)
= 3.2 M. ( 2 significant digit)
Suppose 2.11 g of barium nitrate is dissolved in 50. mL of a 0.20 M aqueous solution of sodium chromate.
Suppose 0.264g of barium acetate is dissolved in 50.mL of a 0.20 M aqueous solution of ammonium sulfate. Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the barium acetate is dissolved in it. Round your answer to 2 significant digits.
Suppose 0.248g of barium nitrate is dissolved in 50.mL of a 18.0mM aqueous solution of sodium chromate. Calculate the final molarity of barium cation in the solution. You can assume the volume of the solution doesn't change when the barium nitrate is dissolved in it.
Suppose 0.0948 g of ammonium nitrate is dissolved in 50 mL of a 39.0 m M aqueous solution of sodium chromate. Calculate the final molarity of nitrate anion in the solution. You can assume the volume of the solution doesn't change when the ammonium nitrate is dissolved in it Round your answer to 2 significant digits.
Suppose 1.32 g of lead(II) nitrate is dissolved in 50. mL of a 0.20 M aqueous solution of ammonium sulfate Calculate the final molarity of nitrate anion in the solution. You can assume the volume of the solution doesn't change when the lead(II) nitrate is dissolved in it. Round your answer to 2 significant digits
Suppose 1.55 g of barium nitrate is dissolved in 250. mL of a 52.0 m M aqueous solution of ammonium sulfate. Calculate the final molarity of nitrate anion in the solution. You can assume the volume of the solution doesn't change when the barium nitrate is dissolved in it Round your answer to 3 significant digits.
Suppose 0.934 g of sodium bromide is dissolved in 50. mL of a 0.10 M aqueous solution of silver nitrate. Calculate the final molarity of bromide anion in the solution. You can assume the volume of the solution doesn't change when the sodium bromide is dissolved in it. Round your answer to 2 significant digits x10
Suppose 6.74g of barium acetate is dissolved in 150.mL of a 0.20 M aqueous solution of ammonium sulfate. Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the barium acetate is dissolved in it. Round your answer to 3 significant digits.
Suppose 0.425g of sodium chloride is dissolved in 50.mL of a 0.50 M aqueous solution of silver nitrate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the sodium chloride is dissolved in it. Be sure your answer has the correct number of significant digits.
Suppose 1.85 g of sodium iodide is dissolved in 100. mL of a 64,0 m M aqueous solution of silver nitrate. Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn't change when the sodium iodide is dissolved in it. Round your answer to 2 significant digits.
Suppose 3.03 g of copper(II) nitrate is dissolved in 200. mL of a 72.0 m M aqueous solution of sodium chromate. Calculate the final molarity of copper(II) cation in the solution. You can assume the volume of the solution doesn't change when the copper(II) nitrate is dissolved in it. Round your answer to 2 significant digits. Пм x 6 ?