Question

1. The function takes three parameters: string array, int arraySize, and string word
2. The function will loop through the string array. If word is found in the array, return the matched element’s position (index) in the array. Otherwise, return -1.
3. When a match is found in the array, the loop should be terminated at the time --- no need to continue the loop.
4. If no match is found, the function should display all elements in the array, as well as the search word.
5. Please make sure the function cannot modify any data in the array.

USE C++

Answer 1

#include <iostream>
using namespace std;
int search(string array[],int arraySize,string word)
{
   int index;
   for(int i=0;i<arraySize;i++)
   {
       if(word==array[i])
       return i;
   }
   cout<<"array elements : ";
   for(int i=0;i<arraySize;i++)
   {
       cout<<array[i]<<" ";
   }
   cout<<"\nThe word is : "<<word;
   return -1;
}
int main() {
   string arr[]={"HomeworkLib","india","us","uk"};
   string word="us";
   int index=search(arr,4,word);
   if(index>=0)
   cout<<"index : "<<index;
   return 0;
}

OUTPUT:-

// If any doubt please comment