10.
Find the critical value tc for the level of confidence c and sample size n.
c = 0.90, n = 4
tc = ± 2.353 |
||
tc = ± 5.841 |
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tc = ± 2.132 |
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tc = ± 1.645 |
solution
n=4
df =n-1=4-1=3
= 1 - C = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
t /2,df = t0.05,3 = ± 2.353 using student t table
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