The table summarizes results from pedestrian deaths that were caused by automobile accidents.
Driver Intoxicated? |
Pedestrian Intoxicated? | |
---|---|---|
Yes | No | |
Yes | 55 | 77 |
No | 233 | 611 |
If one of the pedestrian deaths is randomly selected, find the
probability that the pedestrian was intoxicated. (Round your answer
to 4 decimal places.)
Probability =
B.
Giving a test to a group of students, the grades and gender are summarized below. Round your answers to 4 decimal places.
A | B | C | Total | |
---|---|---|---|---|
Male | 16 | 17 | 13 | 46 |
Female | 11 | 20 | 19 | 50 |
Total | 27 | 37 | 32 | 96 |
If one student is chosen at random,
a. Find the probability that the student got an
A:
b. Find the probability that the student was male AND got an
"A":
c. Find the probability that the student was female OR got a
"C":
d. If one student is chosen at random, find the probability that
the student got an 'B' GIVEN they are male:
Driver Intoxicated? |
Pedestrian Intoxicated? | |
---|---|---|
Yes | No | |
Yes | 55 | 77 |
No | 233 | 611 |
the probability that the pedestrian was intoxicated. =
the probability that the pedestrian was intoxicated. = 0.2951
ans 2 )
A | B | C | Total | |
---|---|---|---|---|
Male | 16 | 17 | 13 | 46 |
Female | 11 | 20 | 19 | 50 |
Total | 27 | 37 | 32 | 96 |
a. the probability that the student got an A = 27/96 =0.2813
b the probability that the student was male AND got an "A" = 16/ 46 =0.3478
c. There are 46 males total and 32 people who got a C So there are 46+32 = 78 people who either are male or got a B
We need to subtract off the 13 males who got C . i.e 78 -13 = 65 now there are 96 student total
P(male OR got a C) = (number who are male or got a C or
both)/(total no. of students )
P(male OR got a C) = 65/96
P(male OR got a C) = 0.6771
d) one student is chosen at random, the probability
that the student got an 'B' GIVEN they are male = 16 / 27
=0.5926
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