A simple random sample of the weights of 19 green M&Ms has a mean of 0.8635g...
- A simple random sample of the weights of 19 green M&Ms has a mean of 0.8635g and a standard deviation of 0.0570. Use a 0.05 significance level to test the claim that the mean weight of all green M&Ms is equal to 0.8535g, which is the mean weight required so that M&Ms have the weight printed on the package label. Do green M&Ms appear to have weights consistent with the package label? Test the claim using the critical value method.
- Null and alternative hypotheses _______________________________
- Critical value(s) _______________________________
- Test Statistic______________________________
- State your conclusion in nontechnical language
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A simple random sample of the weights of 19 green M&Ms has
a mean of 0.8635g...
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