How many atoms of oxygen are in 350 mg of calcium nitrate?
2.07 × 1026
9.48 × 1025
7.7 × 1021
2.1 × 1026
1.3 × 1021
mass of calcium nitrate = 350 mg = 0.350 g
number of moles of calcium nitrate = 0.350 g / 164.088 g/mol = 0.00213 mole
1 mole of calcium nitrate = 6.023*10^23 atoms so
0.00213 mole of calcium nitrate =
= 0.00213 mole of calcium nitrate *(6.023*10^23 atoms / 1 mole of calcium nitrate)
= 1.28*10^21 atoms
Therefore, the number of atoms of calcium nitrate = 1.28*10^21
How many atoms of oxygen are in 350 mg of calcium nitrate? 2.07 × 1026 9.48...
How many atoms are in a 5.00 mg sample of oxygen? 1.9 × 1020 9.4 × 1022 6.0 × 1021 1.9 × 1023 5.3 × 1022
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Example: How many moles of oxygen atoms are there in 0.723 moles of aluminum nitrate, Al(NO3)3?
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