Based on past records, below is the Discrete Probability Distributiondescribing the number of cars a Ford car salesman sells daily. ROUND ALL ANSWERS TO TWO (2) DECIMAL PLACES.
Cars Sold,x |
Probability, P(x) |
xP(x) |
x-E(x) |
[x-E(x)]2 |
[x-E(x)]2P(x) |
7 |
0.30 |
||||
9 |
0.40 |
||||
12 |
0.30 |
||||
Expected Value, E(x) |
Variance |
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Standard Deviation |
Based on past records, below is the Discrete Probability Distributiondescribing the number of cars a Ford...
The number of homes sold by a realtor during a month has the following probability distribution: Number Sold Probability 0 0.10 1 0.40 2 0.50 The standard deviation of the number of homes sold by the realtor during a month is the closest to _______. A) 0.44 B) 1.40 C) 0.66 D) 1.35 The standard deviation of the discrete random variable X is calculated as SD(X)=σ=σ2−−√.SD(X)=σ=σ2. The variance of the discrete random variable X is calculated as Var(X) = σ2=∑(xi–μ)2P(X=xi).
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Calculate the mean, the variance, and the standard deviation of the following discrete probability distribution. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your final answers to 2 decimal places.) x-36-26-15-4P(X=x)0.320.360.210.11MeanVarianceStandard deviation
Discrete probability problems 0.2 pts Question 12 The table below is a discrete probability distribution in which x represents the number of tudents that a statistics tutor may see on any given day and Pix) represents the probability that the tutor sees that number of students. P(x) О.11 0.18 e.36 e.16 e.14 e.es What is the mean of this discrete probability distribution? (Round to the nearest hundredth.) Question 13 0.2 pts The table below is a discrete probability distribution in...
Suppose that past records indicate that the probability that a new car will need a warranty repair in the first 90 days of use is 0.04. If a random sample of 400 new cars is selected, what is the probability that the proportion of new cars needing a warranty repair in the first 90 days will be: a. between 0.05 and 0.06? i.e. P(0.05 sp < 0.06) = ranswer to 4 decimal places). b. above 0.07? i.e. Plp > 0.07)...
Calculate the mean, the variance, and the standard deviation of the following discrete probability distribution. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your final answers to 2 decimal places.) x −31 −22 −12 −7 P(X = x) 0.53 0.27 0.13 0.07 Mean Variance Standard deviation
A discrete random variable X has the following probability distribution: x7778798081 P(x) 0.150.150.200.400.10Compute each of the following quantities. i. P(X = 80) ii. P(x > 80) iii. P(X ≤ 80) iv. The mean, μ of x. v. The variance, σ2 of X. vi. The standard deviation, σ of X.
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