Question

Please help with this.

Modify the program Figure 2.6 (exam1/exam2). 
Ask the user to enter two numbers
Find the result when the first number is divided by the second
Also find the remainder when the first number is divided by the second

In other words, the program used to do this:
68  85
score = 81

Now it should do this 
22 2
Divide = 11  Remainder = 0
If you run it again:
11 2
Divide = 5   Remainder = 1
If you run it again:
20 16
Divide = 1   Remainder = 4

Use integer arithmetic only. NO DECIMAL POINTS.

This is my code

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv) {
  
const int bonus = 10;
int exam1;
int exam2;
int score;

scanf("%d%d", &exam1, &exam2);
score = (exam1 + exam2) / 2 + bonus;
printf("score - %d\n", score);

return (0);
}

Answer 1

/*
 *  C Code for demonstrating division
 */

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv)
{  
  const int bonus = 10;
  int exam1;
  int exam2;
  int divide, remainder;

  scanf("%d%d", &exam1, &exam2);

  divide = exam1 / exam2;
  remainder = exam1 % exam2;

  printf("Divide = %d, Remainder = %d\n", divide, remainder);

  return (0);
}