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How much thermal energy (in J) is required to boil 2.20 kg of water at 100.0°C...

How much thermal energy (in J) is required to boil 2.20 kg of water at 100.0°C into steam at 143.0°C? The latent heat of vaporization of water is 2.26 ✕ 106 J/kg and the specific heat of steam is 2010 J / kg · °C .

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