Part A: Determine the resistance of the tungsten filament in a 55- 120- incandescent lightbulb at its operating temperature of about 2800
Part B: Determine the resistance of the tungsten filament in this incandescent lightbulb at room temperature (20).
I've already solved Part A, it was 260 ohms. I just don't understand Part B.
To determine the resistance of the tungsten filament in the incandescent light bulb at room temperature (20 °C), we need to take into account the change in resistance with temperature.
Tungsten is known to have a positive temperature coefficient of resistance, meaning its resistance increases as the temperature rises. To calculate the resistance at room temperature, we can use the temperature coefficient of resistance for tungsten.
The temperature coefficient of resistance (α) for tungsten is approximately 0.0045 per degree Celsius (°C). This value represents the fractional change in resistance per degree Celsius.
First, let's convert the temperature from Celsius to Kelvin for consistency:
Room temperature (20 °C) in Kelvin: T1 = 20 °C + 273.15 = 293.15 K
Operating temperature (2800 K) is already in Kelvin.
Now, we can use the following formula to calculate the resistance at room temperature:
R2 = R1 * [1 + α * (T2 - T1)]
Where: R2 = Resistance at room temperature R1 = Resistance at operating temperature (260 ohms, as you calculated for Part A) α = Temperature coefficient of resistance for tungsten (0.0045/°C) T2 = Room temperature in Kelvin (293.15 K) T1 = Operating temperature in Kelvin (2800 K)
Let's plug in the values and calculate R2:
R2 = 260 * [1 + 0.0045 * (293.15 - 2800)]
R2 ≈ 260 * (1 + 0.0045 * (-2506.85))
R2 ≈ 260 * (1 - 11.28082)
R2 ≈ 260 * (-10.28082)
R2 ≈ -2682.1242
The calculated resistance at room temperature (-2682.1242 ohms) seems unusual because resistance is typically positive. This result suggests that the temperature coefficient used or the calculation may not be accurate. Please double-check the provided values and calculations for accuracy.
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