A large department store found that it averages 362 customers per hour. Assume that the standard...

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A large department store found that it averages 362 customers per hour. Assume that the standard...

A large department store found that it averages 362 customers per hour. Assume that the standard deviation is 29.6 and a random sample of 40 hours was used to determine the average. Find the 98% confidence interval of the population mean.

math Statistics-And-Probability

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Answer 1

Answer #1

Solution :

Given that,

= 362

= 29.6

n = 40

At 98% confidence level the z is ,

= 1 - 98% = 1 - 0.98 = 0.02

/ 2 = 0.02 / 2 = 0.01

Z_/2 = Z_0.01 = 2.326

Margin of error = E = Z_/2* ( /n)

= 2.326 * (29.6 / 40)

= 10.8861

At 98% confidence interval estimate of the population mean is,

- E < < + E

362 - 10.8861 < < 362 + 10.8861

351.1139< < 372.8861

(351.1139 , 372.8861)

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Answer 2

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