The average annual wind speed in Rochester, Minnesota is 15.5 miles per hour. If a sample of 95 days are used to determine the average wind speed, find the 98% confidence interval of the mean. Assume the standard deviation was 3.2 miles per hour. (Show Work)
Solution :
Given that,
Point estimate = sample mean =
= 15.5
Population standard deviation =
= 3.2
Sample size = n = 95
At 98% confidence level
= 1 - 98%
= 1 - 0.98 =0.02
/2
= 0.01
Z/2
= Z0.01 = 2.33
Margin of error = E = Z/2
* (
/n)
= 2.33 * ( 3.2 / 95
)
= 0.76
At 98% confidence interval estimate of the population mean is,
± E
15.5 ± 0.76
( 14.74, 16.26 )
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