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The acceleration times (in seconds) from 0 to 60 miles per hour for 26 randomly selected...

The acceleration times (in seconds) from 0 to 60 miles per hour for 26 randomly selected sedans had a sample mean of 7.99 seconds and a sample standard deviation of 1.190. Construct a 98% confidence interval for the population standard deviation. Assume the sample is from a normal population. Enter your answer in interval notation. If your left endpoints 5 and your right endpoint is 7, your answer would be (5, 7). Round your endpoints to three decimal places.

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Answer #1

The 98% confidence interval for the population standard deviation

In – 1)52 (n − 1) Tv xy2 V -a2

where

s= 1.190

n= 26

For 98% confidence , g= 0.02

a/2 = 0.01,1 -a/2 =0.99

degrees of freedom = n-1 = 26-1=25

For 98% confidence with df =25

2 = x30 = 44.3141, x 2 = x3 g = 11.5240

Thus ,98% confidence interval for the population standard deviation

(26 - 11.1902 TV 44.3141 (26-111.1902 V 11.5240

=(0.894 , 1.753 )

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